trả lời giúp mình với
a 65-4^x+2=2018^0
b120+2.(3x-17)=2018^0
c 5^2x-3-2.5^2=5^2
d 30-[4:(x-2)+15]=3
e 740:(x+10)=10^2-2.13
g [(6x-39):7].4=12
Tim x:
3^2x-4 -x^0 = 8
65- 4^x+2 = 2014^0
120+2. ( 3x + 17) = 214
5^2x-3 - 2.5^2 = 5^2 = 5^2.3
30- [4(x-2)+15] =3
740:(x+10)= 10^2 - 2.13
[(6x-39):7].4= 12
*
\(3^2x-4-x^0=8\)
9x-4-1=8
9x-5=8
9x=13
=>x=\(\frac{13}{9}\)
trả lời nhanh giúp tôi
Tìm x biết
a) (5x-12):4=318:315
b)5x3-102=35
c)65-4x+2=20180
d)2x+1-2xx=32
e)30-[4(x-2)+15]=3
f)740:(x+10)=102-2.13
Các bạn giúp mình với
a) (5x - 12 ) : 4 = 318 : 315
( 5x - 12 ) : 4 = 33
( 5x - 12 ) : 4 = 27
5x - 12 = 108
5x = 120
x = 24
b) 5x3 - 102 = 35
5x3 - 100 = 35
5x3 = 135
x3 = 27
x3 = 33
=> x = 3
c) 65 - 4x+2 = 20180
65 - 4x+2 = 1
4x+2 = 64
4x+2 = 43
x + 2 = 3
=> x = 1
d) 2x+1 - 2x = 32
2x . ( 2 - 1 ) = 32
2x . 1 = 32
2x = 32
2x = 25
=> x = 5
e) 30 - [ 4( x - 2) + 15 ] = 3
4(x-2) + 15 = 27
4( x-2) = 12
x - 2 = 3
x = 5
f) 740 : ( x + 10 ) = 102 - 2.13
740 : ( x + 10 ) = 100 - 26
740 : ( x + 10 ) = 74
x + 10 = 10
x = 0
a, [8.x-12):4].333=366
b, 41-2x+1=9
c, 32x-4 -x00=8
d, 65-4x+2=201400
e, 120+2.(8x-17)=214
f, 52x-3-2.52=52.3
g, 30-[4.(x-2)+15]=3
h, 740:(x+10)=102-2.13
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Mn giúp mik nha, iu mn
\(a,[\left(8.x-12\right):4].3^3.3=3^6.6\)
\(\left(8x-12\right):4=54\)
\(8x-12=216\)
\(8x=228\)
\(x=28,5\)
\(b,41-2^{x+1}=9\)
\(2^{x+1}=41-9\)
\(2^{x+1}=32\)
\(2^{x+1}=2^5\)
\(\Rightarrow x+1=5\)
\(\Rightarrow x=4\)
giúp mình giải bài toán.......
1)3x-6=5x+2
2)15-x=4x-5
3)x-15=6+4x
4)-12+x=5x-20
5)7x-4=20+3x
6)5x-7=-21-2x
7)x+15=20-4x
8)17-x=7-6x
9)-4|x-2|=-8
10)-7|x+4|=2.(-7)
1) 3x - 6= 5x + 2
5x - 3x = -6 - 2
2x = -8
x = -4
2) 15 - x = 4x - 5
4x + x = 15 + 5
5x = 20
x = 4
Tương tự như trên
1) 3x - 6 = 5x + 2
3x - 5x = 2 + 6
-2x = 8
x = 8 : (-2)
x = -4
2) 15 - x = 4x - 5
-x - 4x = -5 - 15
-5x = -20
x = -20 : (-5)
x = 4
Giúp mình v
Bài10872917292872917 tìm x bt
5x-16=40+x
4x-10=15-x
-12+x=5x-2
7x-4=20+3x
5x-7=20+3x
x+15=7+6x
17-x=7-6x
3x+(-21)=12-8x
125:(3x-13)=25
541+(218-z)=735
3(2x+1)-19=14
175-5(x+3)=85
4x-40=|4|+12
x+15=20-4x
8x+|-3|=-4x+39
6(x-2)+(-2)=20-4x
5x-16=40+x
=> 5x-16-x = 40
=> 5x-x -16=40
4x-16=40
4x= 40+16
4x=56
x= 56:4
x=14
Vậy...
4x-10=15-x
=> 4x-10+x= 15
4x+x -10=15
5x= 15+10
5x= 25
x= 25:5
x=5
Vậy....
5x -16=40+x
=> 5x-x=40+16
=>4x=56
=>x=56:4
x=14
bài 1:
1) 20 - 2(x+4)= 4
2) 30 - [ 4(x-2)+ 15]= 3
3) 14 ⋮(2.x + 3)
4) (3x - 24).7 = 2.73
5) (x + 1)3 = 27
6) (2x - 6).47=49
7) (10 + 2x) : 42011 = 42013
8) [(8x - 12) :4].33 = 36
9) 6⋮(x - 1)
10) (x + 5)⋮(x + 2)
mong mn giúp mình gấp với ạ ^^
1: Ta có: \(20-2\left(x+4\right)=4\)
\(\Leftrightarrow2\left(x+4\right)=16\)
\(\Leftrightarrow x+4=8\)
hay x=4
5: Ta có: \(\left(x+1\right)^3=27\)
\(\Leftrightarrow x+1=3\)
hay x=2
b ) [( 6x - 39) : 7] .4 = 12 c) 4( 3x - 4 ) - 2 = 18 d ) ( 3x - 10 ) :10 = 50
e) x- 7 = - 57 f ) x - [ 42 + (-25) = - 8 g) ( 3x - 24 ) . 73 = 2 . 74
h) x + 5 = 20 - ( 12 -7) k) I x - 5 I = 7 - ( -3) i) I x - 5 I = I 7 I
2x+1 . 22009 = 220010 10 - 2x = 25 - 3x
nik lộn
2x+1. 22009 = 22010
10 - 2x = 25 - 3x
bài 1 ; 6x(x+2018)-3(x+2018)=0
bài 2; x(x-11)+3(11-x)=0
bài 3; x(x-3)-2(3-x)=0
bài 4; 2x(x+5)-4(x+5)=0
mấy bạn giúp mình với ạ
1: =>(x+2018)(6x-3)=0
=>x+2018=0 hoặc 6x-3=0
=>x=1/2 hoặc x=-2018
2: x(x-11)+3(11-x)=0
=>(x-11)(x-3)=0
=>x=11 hoặc x=3
4: =>(x+5)(2x-4)=0
=>2x-4=0 hoặc x+5=0
=>x=2 hoặc x=-5
3: =>(x-3)(x+2)=0
=>x=3 hoặc x=-2
Bài 1:
\(6x\left(x+2018\right)-3\left(x+2018\right)=0\)
\(\Leftrightarrow\left(x+2018\right)\left(6x-3\right)=0\)
\(\Leftrightarrow3\left(x+2018\right)\left(2x-1\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2018\\2x=1\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-2018\\x=\dfrac{1}{2}\end{matrix}\right.\)
Bài 2:
\(x\left(x-11\right)+3\left(11-x\right)=0\)
\(\Leftrightarrow x\left(x-11\right)-3\left(x-11\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(x-11\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=11\end{matrix}\right.\)
Câu 3:
\(x\left(x-3\right)-2\left(3-x\right)=0\)
\(\Leftrightarrow x\left(x-3\right)+2\left(x-3\right)=0\)
\(\Leftrightarrow\left(x-3\right)\left(x+2\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=3\\x=-2\end{matrix}\right.\)
Câu 4:
\(2x\left(x+5\right)-4\left(x+5\right)=0\)
\(\Leftrightarrow\left(x+5\right)\left(2x-4\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-5\\2x=4\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=-5\\x=2\end{matrix}\right.\)